Calling Method, Classmethod, Staticmethod In The Same Python Class
Solution 1:
Yes, your guesses will work. Note that it is also possible/normal to call staticmethods and classmethods outside the class:
class A():
...
A.class_foo()
A.static_foo()
Also note that inside regular instance methods, it's customary to call the staticmethods and class methods directly on the instance (self
) rather than the class (A
):
classA():definstance_method(self):
self.class_foo()
self.static_foo()
This allow for inheritance to work as you might expect -- If I create a B
subclass from A
, if I call B.instance_method()
, my class_foo
function will get B
instead of A
as the cls
argument -- And possibly, if I override static_foo
on B
to do something slightly different than A.static_foo
, this will allow the overridden version to be called as well.
Some examples might make this more clear:
classA(object):
@staticmethoddefstatic():
print("Static, in A")
@staticmethoddefstaticoverride():
print("Static, in A, overrideable")
@classmethoddefclsmethod(cls):
print("class, in A", cls)
@classmethoddefclsmethodoverrideable(cls):
print("class, in A, overridable", cls)
definstance_method(self):
self.static()
self.staticoverride()
self.clsmethod()
self.clsmethodoverride()
classB(A):
@classmethoddefclsmethodoverrideable(cls):
print("class, in B, overridable", cls)
@staticmethoddefstaticoverride():
print("Static, in B, overrideable")
a = A()
b = B()
a.instance_method()
b.instance_method()
...
After you've run that, try it by changing all of the self.
to A.
inside instance_method
. Rerun and compare. You'll see that all of the references to B
have gone (even when you're calling b.instance_method()
). This is why you want to use self
rather than the class.
Solution 2:
As @wim said, what you have is right. Here's the output when My_Question
is called.
>>> a.My_Question("My_Answer=D")
executing foo(<__main__.A object at 0x0000015790FF4668>,My_Answer=D)
executing class_foo(<class '__main__.A'>,My_Answer=D)
executing static_foo(My_Answer=D)
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